# Frequent question: What is the mole ratio of potassium chlorate to oxygen?

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## How many moles are in potassium chlorate?

number of moles given to you from compound 1 ÷ the front number for compound 1 × the front number for another compound. Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.

## What is the experimental ratio of KCL to oxygen?

You’d need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen. Notice that you have a 2:3. mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you’ll always produce 3/2 times more moles of the latter.

1:2:6.

## What is the mole ratio?

Mole Ratio: is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation. The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.

## How many atoms are in 3.75 moles?

There are 2.26 x 1024 carbon atoms in 3.75 moles of carbon. A mole is defined as 6.022 x 1023 elementary entities of a…

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## How many moles of KClO3 are required for producing 2.4 moles of oxygen?

Answer: The amount of KClO3 required 196 g. Given: 196 g of is requires to produce 2.4 moles of oxygen.

## How many moles of oxygen are present in one mole of KClO3?

1 mole of KCLlO3 * (3moles KClO3/2moles O2) = 1.5 moles of O2.

## What is the mole ratio of O2?

The ratio of the number of moles of aluminum to the number of moles of oxygen required in the reaction should be 4/3. When 6.38 moles of O2 and 9.15 moles of Al react, the ratio of aluminum to oxygen is 9.15/6.38 = 1.434.

## How do you find the experimental percentage of oxygen?

The experimental percentage of oxygen in the sample of KClO3 is calculated by using this equation. Experimental % oxygen = Mass of oxygen lost x 100 Mass of KClO3 The theoretical value of the % oxygen in potassium chlorate is calculated from the formula KClO3 with a molar mass = 122.6 g/mol.