How many moles are in potassium chlorate?
number of moles given to you from compound 1 ÷ the front number for compound 1 × the front number for another compound. Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.
What is the experimental ratio of KCL to oxygen?
You’d need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen. Notice that you have a 2:3. mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you’ll always produce 3/2 times more moles of the latter.
What is the mole ratio of potassium to chlorine to oxygen in this compound?
What is the mole ratio?
Mole Ratio: is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation. The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.
How many atoms are in 3.75 moles?
There are 2.26 x 1024 carbon atoms in 3.75 moles of carbon. A mole is defined as 6.022 x 1023 elementary entities of a…
How many moles of KClO3 are required for producing 2.4 moles of oxygen?
Answer: The amount of KClO3 required 196 g. Given: 196 g of is requires to produce 2.4 moles of oxygen.
How many moles of oxygen are present in one mole of KClO3?
1 mole of KCLlO3 * (3moles KClO3/2moles O2) = 1.5 moles of O2.
What is the mole ratio of O2?
The ratio of the number of moles of aluminum to the number of moles of oxygen required in the reaction should be 4/3. When 6.38 moles of O2 and 9.15 moles of Al react, the ratio of aluminum to oxygen is 9.15/6.38 = 1.434.
How do you find the experimental percentage of oxygen?
The experimental percentage of oxygen in the sample of KClO3 is calculated by using this equation. Experimental % oxygen = Mass of oxygen lost x 100 Mass of KClO3 The theoretical value of the % oxygen in potassium chlorate is calculated from the formula KClO3 with a molar mass = 122.6 g/mol.